Maximum number of sections in an aluminum radiator

The size and type of radiators we select are very important factors in efficiently heating our homes. Because of their superior heat conduction qualities and lightweight design, aluminum radiators have become more and more popular. A common query among homeowners is: how many sections does an aluminum radiator need to have in order to heat a room efficiently?

An aluminum radiator’s total heating capacity is increased by each section. In general, a radiator will produce more heat if it has more sections. But one must strike a balance. Although it would make sense to choose the most sections to provide the most heat, there are other considerations to make, like the room’s size, insulation quality, and desired temperature.

It takes more than just turning up the heat to create a constant, comfortable temperature throughout the house without wasting any energy. For a small space, a radiator with too many sections can cause overheating and wasteful energy use. However, if there aren’t enough sections, larger areas or poorly insulated rooms might not get enough heat.

Knowing how many sections your aluminum radiator should have requires taking into account a number of factors unique to your house and heating requirements. We’ll go into more detail about these factors in this post to assist you in making an informed choice that will keep your house warm and comfortable throughout the winter.

Aluminum Radiator Model Maximum Number of Sections
EcoHeat Basic 10 sections
ThermoPro Plus 12 sections
HeatMaster Ultra 15 sections

Example of calculation of sections of aluminum radiators per square meter

The fact that aluminum radiators dissipate heat well is not sufficient information.

It is imperative that you calculate the precise number of them that each room needs before you install them.

If you only know how many aluminum radiators a square meter requires, you can purchase the required number of sections with confidence.

Calculation of sections of aluminum radiators per square meter

Generally speaking, producers have already determined the standard power of aluminum batteries. which is determined by factors like the room’s size and ceiling height. Therefore, it is estimated that a 100 Watt heat output will be needed to heat a 1 m2 room with a ceiling as high as 3 m.

These numbers are approximations because the heating area provided by the aluminum radiators in this instance does not account for potential heat loss from the room or for ceiling heights. These are widely recognized building standards, and the manufacturers’ data sheets for their products list them.

  1. The parameter of heat output of one radiator fin plays an important role. For an aluminum heater it is 180-190 W.
  2. The temperature of the medium must also be taken into account. It can be found out in the controlling heating company, if the heating is centralized, or measured independently in an autonomous system. For aluminum batteries, the indicator is 100-130 degrees. Dividing the temperature by the heat capacity of the radiator, it turns out that to heat 1 m2 will require 0.55 sections.
  3. In the event that the height of the ceilings "outgrew" the classical standards, then a special coefficient must be applied:
  4. if the ceiling is 3 m, the parameters are multiplied by 1.05;
  5. at a height of 3.5 m it is 1.1;
  6. if the indicator is 4 m – it is 1.15;
  7. wall height 4.5 m – the coefficient is 1.2.
  8. It is possible to use the table, which is provided by manufacturers to their products.

What is the required number of aluminum radiator sections?

Using a form that works with any kind of heater, the number of sections of the aluminum radiator is calculated:

  • S – the area of the room where the installation of the radiator is required;
  • k – correction factor of 100 W/m2 depending on the ceiling height;
  • P – capacity of one radiator section.

The number of aluminum radiator sections needed for heating is determined by taking the area of the room (20 m2) times the ceiling height (2.7 m), and finding that an aluminum radiator with a single section’s power of 0.138 kW will require 14 sections.

20 x 100 / 0.138 = 14.49 is Q.

Since the ceiling height in this example is less than 3 meters, the coefficient does not apply. However, even these parts of the heating system with aluminum radiators won’t be accurate because they won’t account for the room’s potential heat loss. Remember that the number of windows, whether the room is in a corner, and whether it has a balcony all indicate how many sources of heat loss there are in the space.

When calculating the amount of space needed for aluminum radiators, you should include the percentage of heat loss based on the location of the radiators:

  • if they are fixed under the window sill, the loss will be up to 4%;
  • installation in a niche instantly increases this figure to 7%;
  • If the aluminum radiator for beauty to cover one side of the screen, the losses will be up to 7-8%;
  • closed by the screen completely, it will lose up to 25%, which makes it in principle unprofitable.

When installing aluminum batteries, there are other indications to consider in addition to these.

Example calculation

When determining the number of aluminum radiator sections required for a 20 m2 room with a 100 W/m2 norm, corrective coefficients of heat loss must also be made.

  • each window adds 0.2 kW;
  • the door "costs" 0.1 kW.

The correction factor will be 1.04 and the formula itself will have the following appearance if it is assumed that the radiator will be positioned beneath the window sill:

(20 x 100 + 0.2 + 0.1) x 1.3 x 1.04 / 72 = 37.56 is the value of Q.

  • first indicator – is the area of the room;
  • second – standard number of watts per m2;
  • third and fourth indicate that the room has one window and one door each;
  • following indicator – is the level of heat output of the aluminum radiator in kW;
  • sixth – correction factor for the location of the radiator.

The heater’s single fin’s heat output should be used to divide everything. The manufacturer’s table, which displays the heating media’s coefficients in relation to the device’s power, can be used to calculate it. One fin’s average value is 180 W, with a correction of 0.4. When water is heated to +60 degrees Celsius, 72 W produces one section, as can be found by multiplying these figures.

The maximum number of sections in an aluminum radiator made especially for this room will be 38 fins because the rounding is done upwards. Splitting the structure into two sections with 19 ribs each will enhance its performance.

Visit our website to get helpful information regarding aluminum radiators:

Calculation by volume

You will need to consult the SNiP norms if you perform these kinds of computations. In addition to considering the radiator’s performance, they also consider the building’s construction material.

For instance, the standard for 1 m2 for a brick house is 34 W, and for panel buildings, it is 41 W. The volume of the room multiplied by the heat input norms and divided by the heat output of one section is how you get the number of battery sections based on the volume of the room.

  1. To calculate the volume of a room of 16 m2, you need to multiply this figure by the height of the ceilings, for example, 3 m (16×3 = 43 m3).
  2. The norm of heat for a brick building = 34 W, to find out what quantity is required for this room, 48 m3 x 34 W (for a panel house at 41 W) = 1632 W.
  3. Determine how many sections are required at a radiator capacity, for example, 140 W. For this 1632 W/ 140 W =11.66.

Rounding this number, we obtain the requirement for a 12-section aluminum radiator in a 48 m³ room.

Thermal capacity of 1 section

The average heat output values are typically specified by the manufacturer in the technical characteristics of heaters. Therefore, it is 1.9–2.0 м2 for aluminum heaters. To calculate the number of sections required, divide the area of the room by this coefficient.

For instance, since 16/ 2 = 8, the same 16 m2 room would need 8 sections.

Because you may experience a cold room following the installation of the structure, these calculations are approximations and cannot be used without accounting for heat loss and the actual conditions of the battery placement.

It is vital to determine the quantity of heat required to heat a specific living space in order to obtain the most accurate numbers. Numerous correction factors will need to be considered for this. This method is particularly crucial when figuring out how much aluminum heating radiators will cost for a private residence.

The following formula is needed:

S x K1 x K2 x K3 x K4 x K5 x K6 x K7 x 100W/m2 = KT

  1. KT – is the amount of heat that the room requires.
  2. S – area.
  3. К1 – coefficient designation for a glazed window. For standard double glazing it is 1.27, for double glazing – 1.0, and for triple – 0.85.
  4. К2 – is the coefficient of the insulation level of the wall. For uninsulated panel it = 1.27, for a brick wall with single layer masonry = 1.0, and in two bricks = 0.85.
  5. К3 – is the ratio of the area occupied by the window to the floor.When in between:
  6. 50% – the coefficient is 1.2;
  7. 40% – 1.1;
  8. 30% – 1.0;
  9. 20% – 0.9;
  10. 10% – 0.8.
  11. К4 – is the coefficient that takes into account the air temperature according to SNiP on the coldest days of the year:
  12. +35 = 1.5;
  13. +25 = 1.2;
  14. +20 = 1.1;
  15. +15 = 0.9;
  16. +10 = 0.7.
  17. К5 indicates correction in the presence of external walls.For example:
  18. when it is alone, the coefficient is 1.1;
  19. two external walls – 1.2;
  20. 3 walls – 1.3;
  21. all four walls – 1.4.
  22. К6 takes into account the presence of a room above the room for which the calculations are being made.Where available:
  23. unheated attic – coefficient 1.0;
  24. heated attic – 0.9;
  25. living room – 0.8.
  26. К7 – is a coefficient that indicates the height of the ceiling in the room:
  27. 2.5 м = 1.0;
  28. 3.0 м = 1.05;
  29. 3.5 м = 1.1;
  30. 4.0 м = 1.15;
  31. 4.5 м = 1.2.

By using this formula, you can anticipate and account for nearly every detail that could have an impact on the living area’s heating. After calculating in accordance with it, one can be certain that the outcome shows the ideal quantity of aluminum radiator sections for a specific space.

It is crucial to be aware of the following information if you choose to install aluminum heating radiators:

Regardless of the calculation principle used, it is crucial to apply it all at once because using the right batteries will not only provide warmth but also result in significant energy cost savings. The latter is particularly crucial when tariffs are continuously rising.

Useful video

When it comes to aluminum radiators for heating your home, the maximum number of sections isn"t just about cramming in as many as possible. Each section of an aluminum radiator contributes to its efficiency and heat output. Generally, the more sections you have, the higher the heat output you can achieve. However, there"s a balance to strike. If you add too many sections, the radiator might not heat up evenly or efficiently, leading to cold spots and wasted energy. It"s crucial to consult with a heating expert or refer to the manufacturer"s guidelines to determine the optimal number of sections for your specific heating needs and room size. This way, you ensure a cozy and energy-efficient home during those chilly months.

How to calculate sections of heating radiators?

What is the ideal number of sections for a radiator?

After surviving the winter, we always had the same objective: to get as ready as we could for the upcoming heating season by swapping out our outdated heating radiators for more energy-efficient ones. After selecting a heating device, you must accurately determine how many heating radiator sections there are. If you are aware of the formula, this task is simple.

It will be required to measure the room’s dimensions and determine its area in order to make accurate calculations. The location of the room—whether it is next to or separate from other rooms—the thickness and type of material of the walls, the quantity of windows, and the level of thermal insulation are all significant considerations.

Standard calculation

Many people lament that the house remains uncomfortable and cold even after replacing the batteries. Experts are certain: the gadgets did not fall short of users’ expectations. The most frequent cause is inaccurate radiator section calculations. The SNiP requirements are taken into account by standard schemes. They claim that 100 W of heater power is required to heat one square meter of living space.

This leads us to a straightforward formula:

S (room area) multiplied by 100 and divided by P (power of one battery section) equals K (number of batteries). The product’s technical passport contains information on the final value.

This is a straightforward example of using the formula. Assume for the moment that a room measuring 22 square meters exists. 22×100/200 = 11

An 11-section radiator must be chosen for this space. and after that in accordance with the situation. If the room is a corner, we receive a little bit extra—13—if we add 20% for reservations. You can calculate practically all radiators, including cast iron and bimetallic ones, using this scheme.

Volumetric calculation of the number of sections

The radiator’s volume can be used to determine the necessary number of sections. If the home or apartment is constructed without considering the current trend of energy-saving technologies, 41 watts of heat capacity are needed for every cubic meter of volume.

Europe makes use of this scheme. We can calculate the necessary power for the device by dividing the available volume of the room by 41. It is simple to determine the sectionality of the device using that information and the same indicator for one battery section.

As an illustration, let us consider a calculation where the room has a 22 square meter area and a 2.7 meter ceiling height. Here’s how to calculate the cubic volume:

The cube is 22×2,7=59,4 м. Plus, 59,4/41 = 1,448 kW.

Contemporary combined battery

Depending on the model, a single radiator unit’s power can range from 120 to 200 W. Here are some computation examples:

  1. If this value is equal to 120 W (parameters are specified in the passport), then the calculation formula is as follows – 1448/120=12.06 (12-section battery).
  2. If the power of one unit of the device is equal to 250 W, then the following figures are obtained – 1448/250=5.8 (6-section battery). The principle of calculations is generally clear.

Most of the store’s sellers are aware of the heater’s power. It is known that this indicator equals 160 W for a section of a cast-iron unit, 192 W for aluminum, and 200 W for bimetallic units. With these values in mind, precise calculations can be made ahead of time, prior to purchase.

Kindly take note! Experts recommend adding 20% more to the exact calculations because winters can be particularly harsh in our latitudes. This implies that the sectionality of the appliance should always be increased by two units from the figure you were given.

One of the most frequent queries from homeowners regarding aluminum radiators is how many sections they can have. Though there is a limit to take into account, more sections usually equate to more heat output.

Aluminum radiators are renowned for their rapid heat distribution and efficiency. Over-stacking sections, though, might not always be the best course of action. The weight added by each section may increase the strain on your wall mounts or brackets. Furthermore, an overly large radiator may not fit properly in every space, creating problems with both functionality and aesthetics.

Achieving a balance between your home’s heating requirements and the functional constraints of your area is essential. Speaking with a heating specialist can offer insightful advice catered to your particular circumstances. They can assist you in figuring out how many sections you should have in order to maintain the integrity and beauty of your living area and achieve the best possible heating efficiency.

Recall that the objective is to provide your home with a comfortable and energy-efficient heating solution, not just to maximize the number of sections. You can enjoy a warm and comfortable home environment during the winter months without needless hassles if you make educated decisions and take into account both heating requirements and practical constraints.

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Sergey Ivanov

I like to help people create comfort and comfort in their homes. I share my experience and knowledge in articles so that you can make the right choice of a heating and insulation system for your home.

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